Base | Representation |
---|---|
bin | 10011101101101011100… |
… | …000101001100000111000 |
3 | 11210111202122201010220021 |
4 | 103231223200221200320 |
5 | 134143430403402000 |
6 | 2514203221140224 |
7 | 166606120364632 |
oct | 23555340514070 |
9 | 4714678633807 |
10 | 1354718419000 |
11 | 482595259281 |
12 | 19a67855a674 |
13 | 9a99857686b |
14 | 497d67dda52 |
15 | 2538cb5011a |
hex | 13b6b829838 |
1354718419000 has 64 divisors (see below), whose sum is σ = 3170400236640. Its totient is φ = 541825977600.
The previous prime is 1354718418997. The next prime is 1354718419013. The reversal of 1354718419000 is 9148174531.
It is a happy number.
It is a super-2 number, since 2×13547184190002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9330964 + ... + 9475036.
Almost surely, 21354718419000 is an apocalyptic number.
1354718419000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1354718419000 is an abundant number, since it is smaller than the sum of its proper divisors (1815681817640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1354718419000 is a wasteful number, since it uses less digits than its factorization.
1354718419000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 153497 (or 153483 counting only the distinct ones).
The product of its (nonzero) digits is 120960, while the sum is 43.
The spelling of 1354718419000 in words is "one trillion, three hundred fifty-four billion, seven hundred eighteen million, four hundred nineteen thousand".
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