Base | Representation |
---|---|
bin | 1100010100110101101010… |
… | …0111001001010011100010 |
3 | 1202222120110002010210222011 |
4 | 3011031122213021103202 |
5 | 3234014241324430200 |
6 | 44453433524303134 |
7 | 2566052466412261 |
oct | 305153247112342 |
9 | 52876402123864 |
10 | 13552142030050 |
11 | 4355481966108 |
12 | 162a5b4b41aaa |
13 | 773c6658b5c0 |
14 | 34bcda2465d8 |
15 | 1877c7c2a5ba |
hex | c535a9c94e2 |
13552142030050 has 24 divisors (see below), whose sum is σ = 27145982959956. Its totient is φ = 5003867826240.
The previous prime is 13552142030039. The next prime is 13552142030087. The reversal of 13552142030050 is 5003024125531.
It can be written as a sum of positive squares in 6 ways, for example, as 6356716690009 + 7195425340041 = 2521253^2 + 2682429^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13552142029994 and 13552142030021.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10424723989 + ... + 10424725288.
Almost surely, 213552142030050 is an apocalyptic number.
13552142030050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13552142030050 is an abundant number, since it is smaller than the sum of its proper divisors (13593840929906).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13552142030050 is a wasteful number, since it uses less digits than its factorization.
13552142030050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20849449302 (or 20849449297 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 13552142030050 its reverse (5003024125531), we get a palindrome (18555166155581).
The spelling of 13552142030050 in words is "thirteen trillion, five hundred fifty-two billion, one hundred forty-two million, thirty thousand, fifty".
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