Search a number
-
+
13552311300 = 223521173101557
BaseRepresentation
bin11001001111100011…
…11101110000000100
31021222111001202010120
430213301331300010
5210223342430200
610120441021540
7656560513443
oct144761756004
937874052116
1013552311300
115824a21080
1227627848b0
13137c941218
14927c5ad5a
15544b9e9a0
hex327c7dc04

13552311300 has 288 divisors, whose sum is σ = 43869942144. Its totient is φ = 3202560000.

The previous prime is 13552311287. The next prime is 13552311319. The reversal of 13552311300 is 311325531.

13552311300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 24330622 + ... + 24331178.

It is an arithmetic number, because the mean of its divisors is an integer number (152326188).

Almost surely, 213552311300 is an apocalyptic number.

13552311300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13552311300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21934971072).

13552311300 is an abundant number, since it is smaller than the sum of its proper divisors (30317630844).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13552311300 is a wasteful number, since it uses less digits than its factorization.

13552311300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 759 (or 752 counting only the distinct ones).

The product of its (nonzero) digits is 1350, while the sum is 24.

Adding to 13552311300 its reverse (311325531), we get a palindrome (13863636831).

It can be divided in two parts, 1355231 and 1300, that added together give a palindrome (1356531).

The spelling of 13552311300 in words is "thirteen billion, five hundred fifty-two million, three hundred eleven thousand, three hundred".