Base | Representation |
---|---|
bin | 10011101110010110101… |
… | …111100000011011101111 |
3 | 11210120122012111222101020 |
4 | 103232112233200123233 |
5 | 134201422043444010 |
6 | 2514403211145223 |
7 | 166633105433442 |
oct | 23562657403357 |
9 | 4716565458336 |
10 | 1355443734255 |
11 | 482927719376 |
12 | 19a83b445213 |
13 | 9aa8290a7a0 |
14 | 49864c87659 |
15 | 253d1673470 |
hex | 13b96be06ef |
1355443734255 has 32 divisors (see below), whose sum is σ = 2336732798400. Its totient is φ = 666952811520.
The previous prime is 1355443734199. The next prime is 1355443734301. The reversal of 1355443734255 is 5524373445531.
It is not a de Polignac number, because 1355443734255 - 214 = 1355443717871 is a prime.
It is a super-2 number, since 2×13554437342552 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1355443734198 and 1355443734207.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1403166 + ... + 2163275.
It is an arithmetic number, because the mean of its divisors is an integer number (73022899950).
Almost surely, 21355443734255 is an apocalyptic number.
1355443734255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1355443734255 is a deficient number, since it is larger than the sum of its proper divisors (981289064145).
1355443734255 is a wasteful number, since it uses less digits than its factorization.
1355443734255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3568411.
The product of its digits is 15120000, while the sum is 51.
The spelling of 1355443734255 in words is "one trillion, three hundred fifty-five billion, four hundred forty-three million, seven hundred thirty-four thousand, two hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •