Base | Representation |
---|---|
bin | 1100010101100111001001… |
… | …1011111000100101011111 |
3 | 1210000211201220110120100200 |
4 | 3011121302123320211133 |
5 | 3234223443204224210 |
6 | 44503512043354543 |
7 | 2600032626601263 |
oct | 305316233704537 |
9 | 53024656416320 |
10 | 13565426633055 |
11 | 4360079758a60 |
12 | 16310a1b22a53 |
13 | 7752a28c9b3b |
14 | 34c7da6d80a3 |
15 | 187d041490c0 |
hex | c56726f895f |
13565426633055 has 24 divisors (see below), whose sum is σ = 25650988543440. Its totient is φ = 6577176549120.
The previous prime is 13565426633047. The next prime is 13565426633107. The reversal of 13565426633055 is 55033662456531.
13565426633055 is a `hidden beast` number, since 1 + 3 + 5 + 6 + 542 + 6 + 63 + 30 + 5 + 5 = 666.
It is not a de Polignac number, because 13565426633055 - 23 = 13565426633047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13565426632992 and 13565426633010.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 13702450650 + ... + 13702451639.
It is an arithmetic number, because the mean of its divisors is an integer number (1068791189310).
Almost surely, 213565426633055 is an apocalyptic number.
13565426633055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13565426633055 is a deficient number, since it is larger than the sum of its proper divisors (12085561910385).
13565426633055 is a wasteful number, since it uses less digits than its factorization.
13565426633055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27404902311 (or 27404902308 counting only the distinct ones).
The product of its (nonzero) digits is 29160000, while the sum is 54.
The spelling of 13565426633055 in words is "thirteen trillion, five hundred sixty-five billion, four hundred twenty-six million, six hundred thirty-three thousand, fifty-five".
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