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1360404331145 = 51719842355623
BaseRepresentation
bin10011110010111110011…
…010101011101010001001
311211001102220202102000222
4103302332122223222021
5134242102002044040
62520543334035425
7200200042010156
oct23627632535211
94731386672028
101360404331145
11484a42863222
1219b7a47a8b75
139b393551412
1449bb5a0d22d
15255c1de4bb5
hex13cbe6aba89

1360404331145 has 16 divisors (see below), whose sum is σ = 1819488147840. Its totient is φ = 970393676544.

The previous prime is 1360404331103. The next prime is 1360404331189. The reversal of 1360404331145 is 5411334040631.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 1360404331145 - 28 = 1360404330889 is a prime.

It is a super-2 number, since 2×13604043311452 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 421176197 + ... + 421179426.

It is an arithmetic number, because the mean of its divisors is an integer number (113718009240).

Almost surely, 21360404331145 is an apocalyptic number.

It is an amenable number.

1360404331145 is a deficient number, since it is larger than the sum of its proper divisors (459083816695).

1360404331145 is a wasteful number, since it uses less digits than its factorization.

1360404331145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 842355664.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 1360404331145 its reverse (5411334040631), we get a palindrome (6771738371776).

The spelling of 1360404331145 in words is "one trillion, three hundred sixty billion, four hundred four million, three hundred thirty-one thousand, one hundred forty-five".

Divisors: 1 5 17 19 85 95 323 1615 842355623 4211778115 14320045591 16004756837 71600227955 80023784185 272080866229 1360404331145