Base | Representation |
---|---|
bin | 10011110010111110011… |
… | …010101011101010001001 |
3 | 11211001102220202102000222 |
4 | 103302332122223222021 |
5 | 134242102002044040 |
6 | 2520543334035425 |
7 | 200200042010156 |
oct | 23627632535211 |
9 | 4731386672028 |
10 | 1360404331145 |
11 | 484a42863222 |
12 | 19b7a47a8b75 |
13 | 9b393551412 |
14 | 49bb5a0d22d |
15 | 255c1de4bb5 |
hex | 13cbe6aba89 |
1360404331145 has 16 divisors (see below), whose sum is σ = 1819488147840. Its totient is φ = 970393676544.
The previous prime is 1360404331103. The next prime is 1360404331189. The reversal of 1360404331145 is 5411334040631.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 1360404331145 - 28 = 1360404330889 is a prime.
It is a super-2 number, since 2×13604043311452 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 421176197 + ... + 421179426.
It is an arithmetic number, because the mean of its divisors is an integer number (113718009240).
Almost surely, 21360404331145 is an apocalyptic number.
It is an amenable number.
1360404331145 is a deficient number, since it is larger than the sum of its proper divisors (459083816695).
1360404331145 is a wasteful number, since it uses less digits than its factorization.
1360404331145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 842355664.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 1360404331145 its reverse (5411334040631), we get a palindrome (6771738371776).
The spelling of 1360404331145 in words is "one trillion, three hundred sixty billion, four hundred four million, three hundred thirty-one thousand, one hundred forty-five".
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