13642241140 has 48 divisors (see below), whose sum is σ = 32097832704. Its totient is φ = 4826736000.

The previous prime is 13642241131. The next prime is 13642241143. The reversal of 13642241140 is 4114224631.

It is a super-2 number, since 2×13642241140² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13642241099 and 13642241108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13642241143) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 829836 + ... + 846115.

It is an arithmetic number, because the mean of its divisors is an integer number (668704848).

Almost surely, 2^13642241140 is an apocalyptic number.

13642241140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13642241140 is an abundant number, since it is smaller than the sum of its proper divisors (18455591564).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13642241140 is a wasteful number, since it uses less digits than its factorization.

13642241140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1676008 (or 1676006 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 13642241140 its reverse (4114224631), we get a palindrome (17756465771).

The spelling of 13642241140 in words is "thirteen billion, six hundred forty-two million, two hundred forty-one thousand, one hundred forty".