Base | Representation |
---|---|
bin | 11111010011111100111000… |
… | …010110111111111111111010 |
3 | 200001120222211021010122202210 |
4 | 133103330320112333333322 |
5 | 121022222031340340200 |
6 | 1204515153321435550 |
7 | 41002153056061251 |
oct | 3723747026777772 |
9 | 601528737118683 |
10 | 137710481965050 |
11 | 3a973761a676a5 |
12 | 1354126993bbb6 |
13 | 5bac072b47117 |
14 | 260131987b798 |
15 | 10dc2741b2650 |
hex | 7d3f385bfffa |
137710481965050 has 96 divisors (see below), whose sum is σ = 365062748238720. Its totient is φ = 34269416473600.
The previous prime is 137710481965019. The next prime is 137710481965051. The reversal of 137710481965050 is 50569184017731.
It is a super-2 number, since 2×1377104819650502 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (137710481965051) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 486640035 + ... + 486922934.
It is an arithmetic number, because the mean of its divisors is an integer number (3802736960820).
Almost surely, 2137710481965050 is an apocalyptic number.
137710481965050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
137710481965050 is an abundant number, since it is smaller than the sum of its proper divisors (227352266273670).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
137710481965050 is a wasteful number, since it uses less digits than its factorization.
137710481965050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 973563048 (or 973563043 counting only the distinct ones).
The product of its (nonzero) digits is 6350400, while the sum is 57.
The spelling of 137710481965050 in words is "one hundred thirty-seven trillion, seven hundred ten billion, four hundred eighty-one million, nine hundred sixty-five thousand, fifty".
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