Base | Representation |
---|---|
bin | 10100011000010110010… |
… | …001110101100100111001 |
3 | 11221220000120010202020011 |
4 | 110120112101311210321 |
5 | 140421242434110040 |
6 | 2551221313101521 |
7 | 203120342016535 |
oct | 24302621654471 |
9 | 4856016122204 |
10 | 1400533113145 |
11 | 49aa65481071 |
12 | 1a75238578a1 |
13 | a20ba1b3c3a |
14 | 4bb01340bc5 |
15 | 2666ed693ea |
hex | 14616475939 |
1400533113145 has 64 divisors (see below), whose sum is σ = 1769319383040. Its totient is φ = 1063310976000.
The previous prime is 1400533113139. The next prime is 1400533113157. The reversal of 1400533113145 is 5413113350041.
It is not a de Polignac number, because 1400533113145 - 211 = 1400533111097 is a prime.
It is a super-2 number, since 2×14005331131452 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1166138545 + ... + 1166139745.
It is an arithmetic number, because the mean of its divisors is an integer number (27645615360).
Almost surely, 21400533113145 is an apocalyptic number.
It is an amenable number.
1400533113145 is a deficient number, since it is larger than the sum of its proper divisors (368786269895).
1400533113145 is a wasteful number, since it uses less digits than its factorization.
1400533113145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2366.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 1400533113145 its reverse (5413113350041), we get a palindrome (6813646463186).
The spelling of 1400533113145 in words is "one trillion, four hundred billion, five hundred thirty-three million, one hundred thirteen thousand, one hundred forty-five".
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