Search a number
-
+
140400212135 = 528080042427
BaseRepresentation
bin1000001011000010000…
…0010011100010100111
3111102101201202202120212
42002300200103202213
54300014423242020
6144255435450035
713100151053351
oct2026040234247
9442351682525
10140400212135
11545a8294477
12232638b691b
1310316779001
146b1c84a0d1
1539bae27cc5
hex20b08138a7

140400212135 has 4 divisors (see below), whose sum is σ = 168480254568. Its totient is φ = 112320169704.

The previous prime is 140400212129. The next prime is 140400212149. The reversal of 140400212135 is 531212004041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140400212135 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 140400212135.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14040021209 + ... + 14040021218.

It is an arithmetic number, because the mean of its divisors is an integer number (42120063642).

Almost surely, 2140400212135 is an apocalyptic number.

140400212135 is a deficient number, since it is larger than the sum of its proper divisors (28080042433).

140400212135 is an equidigital number, since it uses as much as digits as its factorization.

140400212135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28080042432.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 140400212135 its reverse (531212004041), we get a palindrome (671612216176).

The spelling of 140400212135 in words is "one hundred forty billion, four hundred million, two hundred twelve thousand, one hundred thirty-five".

Divisors: 1 5 28080042427 140400212135