14040132111020 has 24 divisors (see below), whose sum is σ = 29776200976368. Its totient is φ = 5560448360000.

The previous prime is 14040132111007. The next prime is 14040132111091. The reversal of 14040132111020 is 2011123104041.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 14040132110983 and 14040132111001.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3475278206 + ... + 3475282245.

It is an arithmetic number, because the mean of its divisors is an integer number (1240675040682).

Almost surely, 2^{14040132111020} is an apocalyptic number.

14040132111020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14040132111020 is an abundant number, since it is smaller than the sum of its proper divisors (15736068865348).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14040132111020 is a wasteful number, since it uses less digits than its factorization.

14040132111020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6950560561 (or 6950560559 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 14040132111020 its reverse (2011123104041), we get a palindrome (16051255215061).

The spelling of 14040132111020 in words is "fourteen trillion, forty billion, one hundred thirty-two million, one hundred eleven thousand, twenty".