Base | Representation |
---|---|
bin | 1100110001010000010010… |
… | …0110100111111010100010 |
3 | 1211201020112102010200111201 |
4 | 3030110010212213322202 |
5 | 3320014041240340300 |
6 | 45510011510431414 |
7 | 2646244231064125 |
oct | 314240446477242 |
9 | 54636472120451 |
10 | 14040325324450 |
11 | 4523517684807 |
12 | 16a913866256a |
13 | 7aacc6530089 |
14 | 3677abd223bc |
15 | 19534b24766a |
hex | cc5049a7ea2 |
14040325324450 has 24 divisors (see below), whose sum is σ = 27250440110208. Its totient is φ = 5371950558480.
The previous prime is 14040325324447. The next prime is 14040325324463. The reversal of 14040325324450 is 5442352304041.
It is a super-3 number, since 3×140403253244503 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6104488122 + ... + 6104490421.
It is an arithmetic number, because the mean of its divisors is an integer number (1135435004592).
Almost surely, 214040325324450 is an apocalyptic number.
14040325324450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14040325324450 is a deficient number, since it is larger than the sum of its proper divisors (13210114785758).
14040325324450 is a wasteful number, since it uses less digits than its factorization.
14040325324450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12208978578 (or 12208978573 counting only the distinct ones).
The product of its (nonzero) digits is 230400, while the sum is 37.
Adding to 14040325324450 its reverse (5442352304041), we get a palindrome (19482677628491).
The spelling of 14040325324450 in words is "fourteen trillion, forty billion, three hundred twenty-five million, three hundred twenty-four thousand, four hundred fifty".
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