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140483111 is a prime number
BaseRepresentation
bin10000101111110…
…01101000100111
3100210100021121012
420113321220213
5241430424421
621535012435
73324041516
oct1027715047
9323307535
10140483111
117233204a
123b06a11b
1323149202
141492c67d
15c4ee95b
hex85f9a27

140483111 has 2 divisors, whose sum is σ = 140483112. Its totient is φ = 140483110.

The previous prime is 140483099. The next prime is 140483113. The reversal of 140483111 is 111384041.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140483111 - 222 = 136288807 is a prime.

Together with 140483113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140483113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70241555 + 70241556.

It is an arithmetic number, because the mean of its divisors is an integer number (70241556).

Almost surely, 2140483111 is an apocalyptic number.

140483111 is a deficient number, since it is larger than the sum of its proper divisors (1).

140483111 is an equidigital number, since it uses as much as digits as its factorization.

140483111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

The square root of 140483111 is about 11852.5571502524. The cubic root of 140483111 is about 519.8459985281.

The spelling of 140483111 in words is "one hundred forty million, four hundred eighty-three thousand, one hundred eleven".