141041213 has 2 divisors, whose sum is σ = 141041214. Its totient is φ = 141041212.

The previous prime is 141041209. The next prime is 141041249. The reversal of 141041213 is 312140141.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81396484 + 59644729 = 9022^2 + 7723^2 .

It is an emirp because it is prime and its reverse (312140141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141041213 - 2² = 141041209 is a prime.

It is a super-2 number, since 2×141041213² = 39785247529022738, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141041191 and 141041200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141041293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70520606 + 70520607.

It is an arithmetic number, because the mean of its divisors is an integer number (70520607).

Almost surely, 2^141041213 is an apocalyptic number.

It is an amenable number.

141041213 is a deficient number, since it is larger than the sum of its proper divisors (1).

141041213 is an equidigital number, since it uses as much as digits as its factorization.

141041213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 141041213 is about 11876.0773406037. The cubic root of 141041213 is about 520.5334921727.

Adding to 141041213 its reverse (312140141), we get a palindrome (453181354).

The spelling of 141041213 in words is "one hundred forty-one million, forty-one thousand, two hundred thirteen".