Base | Representation |
---|---|
bin | 1000001101011011010… |
… | …1001011111010011000 |
3 | 111111001112200221201102 |
4 | 2003112311023322120 |
5 | 4302324031020440 |
6 | 144443325410532 |
7 | 13122116406245 |
oct | 2032665137230 |
9 | 444045627642 |
10 | 141043220120 |
11 | 548a8247930 |
12 | 23403109a48 |
13 | 103b9a525ca |
14 | 6b7ddca5cc |
15 | 3a075ddb15 |
hex | 20d6d4be98 |
141043220120 has 32 divisors (see below), whose sum is σ = 346196995920. Its totient is φ = 51288443520.
The previous prime is 141043220113. The next prime is 141043220147. The reversal of 141043220120 is 21022340141.
141043220120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 141043220092 and 141043220101.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 160275947 + ... + 160276826.
Almost surely, 2141043220120 is an apocalyptic number.
141043220120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
141043220120 is an abundant number, since it is smaller than the sum of its proper divisors (205153775800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141043220120 is a wasteful number, since it uses less digits than its factorization.
141043220120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 320552795 (or 320552791 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 141043220120 its reverse (21022340141), we get a palindrome (162065560261).
It can be divided in two parts, 141043 and 220120, that added together give a palindrome (361163).
The spelling of 141043220120 in words is "one hundred forty-one billion, forty-three million, two hundred twenty thousand, one hundred twenty".
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