Base | Representation |
---|---|
bin | 100000000100110110001111… |
… | …001000111101010100101111 |
3 | 200111111012212211101210201221 |
4 | 200010312033020331110233 |
5 | 121442300043143433333 |
6 | 1220010535014244211 |
7 | 41500005014646133 |
oct | 4004661710752457 |
9 | 614435784353657 |
10 | 141070602327343 |
11 | 40a497853466a7 |
12 | 139a4517356667 |
13 | 6093b92b558a0 |
14 | 26b9bd433b3c3 |
15 | 1149884190d2d |
hex | 804d8f23d52f |
141070602327343 has 4 divisors (see below), whose sum is σ = 151922187121768. Its totient is φ = 130219017532920.
The previous prime is 141070602327331. The next prime is 141070602327373. The reversal of 141070602327343 is 343723206070141.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141070602327343 - 25 = 141070602327311 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 141070602327343.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141070602327313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5425792397193 + ... + 5425792397218.
It is an arithmetic number, because the mean of its divisors is an integer number (37980546780442).
Almost surely, 2141070602327343 is an apocalyptic number.
141070602327343 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
141070602327343 is a deficient number, since it is larger than the sum of its proper divisors (10851584794425).
141070602327343 is a wasteful number, since it uses less digits than its factorization.
141070602327343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10851584794424.
The product of its (nonzero) digits is 508032, while the sum is 43.
Adding to 141070602327343 its reverse (343723206070141), we get a palindrome (484793808397484).
The spelling of 141070602327343 in words is "one hundred forty-one trillion, seventy billion, six hundred two million, three hundred twenty-seven thousand, three hundred forty-three".
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