Base | Representation |
---|---|
bin | 11010010010001101… |
… | …10001010010011000 |
3 | 1100102110010002000202 |
4 | 31021012301102120 |
5 | 212400010212100 |
6 | 10252132321332 |
7 | 1006460014640 |
oct | 151106612230 |
9 | 40373102022 |
10 | 14111413400 |
11 | 5a91585827 |
12 | 2899a73248 |
13 | 143b71a676 |
14 | 97c1d9520 |
15 | 578cde7d5 |
hex | 3491b1498 |
14111413400 has 96 divisors (see below), whose sum is σ = 37520336640. Its totient is φ = 4835064960.
The previous prime is 14111413391. The next prime is 14111413447. The reversal of 14111413400 is 431411141.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3502187 + ... + 3506213.
It is an arithmetic number, because the mean of its divisors is an integer number (390836840).
Almost surely, 214111413400 is an apocalyptic number.
14111413400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 14111413400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18760168320).
14111413400 is an abundant number, since it is smaller than the sum of its proper divisors (23408923240).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14111413400 is a wasteful number, since it uses less digits than its factorization.
14111413400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6553 (or 6544 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 14111413400 its reverse (431411141), we get a palindrome (14542824541).
The spelling of 14111413400 in words is "fourteen billion, one hundred eleven million, four hundred thirteen thousand, four hundred".
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