Base | Representation |
---|---|
bin | 1100110101011011010111… |
… | …1011110110011000011100 |
3 | 1211222002120221012010212211 |
4 | 3031112311323312120130 |
5 | 3322202404100321300 |
6 | 50002550015010204 |
7 | 2654363003151454 |
oct | 315266573663034 |
9 | 54862527163784 |
10 | 14112019932700 |
11 | 4550968397068 |
12 | 16bb006b09964 |
13 | 7b49b0a86ab1 |
14 | 36b04da18d64 |
15 | 1971454e44ba |
hex | cd5b5ef661c |
14112019932700 has 72 divisors (see below), whose sum is σ = 30692372531184. Its totient is φ = 5632038720000.
The previous prime is 14112019932641. The next prime is 14112019932779. The reversal of 14112019932700 is 723991021141.
It is a super-2 number, since 2×141120199327002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 588454710 + ... + 588478690.
It is an arithmetic number, because the mean of its divisors is an integer number (426282951822).
Almost surely, 214112019932700 is an apocalyptic number.
14112019932700 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14112019932700 is an abundant number, since it is smaller than the sum of its proper divisors (16580352598484).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14112019932700 is a wasteful number, since it uses less digits than its factorization.
14112019932700 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37063 (or 37056 counting only the distinct ones).
The product of its (nonzero) digits is 27216, while the sum is 40.
The spelling of 14112019932700 in words is "fourteen trillion, one hundred twelve billion, nineteen million, nine hundred thirty-two thousand, seven hundred".
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