Base | Representation |
---|---|
bin | 1100110101011011010111… |
… | …1101110000000111000100 |
3 | 1211222002120222010110211111 |
4 | 3031112311331300013010 |
5 | 3322202404212300200 |
6 | 50002550033414404 |
7 | 2654363010326221 |
oct | 315266575600704 |
9 | 54862528113744 |
10 | 14112020431300 |
11 | 45509686a7730 |
12 | 16bb00710a404 |
13 | 7b49b0bcca1c |
14 | 36b04db08948 |
15 | 1971455920ba |
hex | cd5b5f701c4 |
14112020431300 has 144 divisors (see below), whose sum is σ = 35715542308992. Its totient is φ = 4782890649600.
The previous prime is 14112020431297. The next prime is 14112020431319. The reversal of 14112020431300 is 313402021141.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1737267 + ... + 5589466.
It is an arithmetic number, because the mean of its divisors is an integer number (248024599368).
Almost surely, 214112020431300 is an apocalyptic number.
14112020431300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14112020431300 is an abundant number, since it is smaller than the sum of its proper divisors (21603521877692).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14112020431300 is a wasteful number, since it uses less digits than its factorization.
14112020431300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7326878 (or 7326871 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 14112020431300 its reverse (313402021141), we get a palindrome (14425422452441).
The spelling of 14112020431300 in words is "fourteen trillion, one hundred twelve billion, twenty million, four hundred thirty-one thousand, three hundred".
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