1411213301 has 2 divisors, whose sum is σ = 1411213302. Its totient is φ = 1411213300.

The previous prime is 1411213273. The next prime is 1411213303. The reversal of 1411213301 is 1033121141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1166290801 + 244922500 = 34151^2 + 15650^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1411213301 is a prime.

Together with 1411213303, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1411213301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1411213303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705606650 + 705606651.

It is an arithmetic number, because the mean of its divisors is an integer number (705606651).

Almost surely, 2^1411213301 is an apocalyptic number.

It is an amenable number.

1411213301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411213301 is an equidigital number, since it uses as much as digits as its factorization.

1411213301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1411213301 is about 37566.1190569375. The cubic root of 1411213301 is about 1121.6677166414.

Adding to 1411213301 its reverse (1033121141), we get a palindrome (2444334442).

The spelling of 1411213301 in words is "one billion, four hundred eleven million, two hundred thirteen thousand, three hundred one".