141131104120120 has 16 divisors (see below), whose sum is σ = 317544984270360. Its totient is φ = 56452441648032.

The previous prime is 141131104120087. The next prime is 141131104120121. The reversal of 141131104120120 is 21021401131141.

It is a junction number, because it is equal to n+sod(n) for n = 141131104120091 and 141131104120100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141131104120121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1764138801462 + ... + 1764138801541.

Almost surely, 2^{141131104120120} is an apocalyptic number.

141131104120120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

141131104120120 is an abundant number, since it is smaller than the sum of its proper divisors (176413880150240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141131104120120 is a wasteful number, since it uses less digits than its factorization.

141131104120120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3528277603014 (or 3528277603010 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 141131104120120 its reverse (21021401131141), we get a palindrome (162152505251261).

The spelling of 141131104120120 in words is "one hundred forty-one trillion, one hundred thirty-one billion, one hundred four million, one hundred twenty thousand, one hundred twenty".