141131211311000 has 128 divisors (see below), whose sum is σ = 335877863630400. Its totient is φ = 55490140108800.

The previous prime is 141131211310963. The next prime is 141131211311003. The reversal of 141131211311000 is 113112131141.

141131211311000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×141131211311000² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141131211311003) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 620153234 + ... + 620380766.

Almost surely, 2^{141131211311000} is an apocalyptic number.

141131211311000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 141131211311000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (167938931815200).

141131211311000 is an abundant number, since it is smaller than the sum of its proper divisors (194746652319400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141131211311000 is a wasteful number, since it uses less digits than its factorization.

141131211311000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 238126 (or 238112 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 141131211311000 its reverse (113112131141), we get a palindrome (141244323442141).

The spelling of 141131211311000 in words is "one hundred forty-one trillion, one hundred thirty-one billion, two hundred eleven million, three hundred eleven thousand".