Search a number
-
+
141132014 = 270566007
BaseRepresentation
bin10000110100110…
…00000011101110
3100211120020201122
420122120003232
5242112211024
622000540542
73332413412
oct1032300356
9324506648
10141132014
1172735631
123b321752
132331568a
1414a5ad42
15c5cbd5e
hex86980ee

141132014 has 4 divisors (see below), whose sum is σ = 211698024. Its totient is φ = 70566006.

The previous prime is 141132007. The next prime is 141132031. The reversal of 141132014 is 410231141.

It is a happy number.

141132014 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×1411320143 (a number of 25 digits) contains 333 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 141131983 and 141132001.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35283002 + ... + 35283005.

It is an arithmetic number, because the mean of its divisors is an integer number (52924506).

Almost surely, 2141132014 is an apocalyptic number.

141132014 is a deficient number, since it is larger than the sum of its proper divisors (70566010).

141132014 is an equidigital number, since it uses as much as digits as its factorization.

141132014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70566009.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 141132014 is about 11879.8995787001. The cubic root of 141132014 is about 520.6451730574.

Adding to 141132014 its reverse (410231141), we get a palindrome (551363155).

The spelling of 141132014 in words is "one hundred forty-one million, one hundred thirty-two thousand, fourteen".

Divisors: 1 2 70566007 141132014