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141132015 = 3253136267
BaseRepresentation
bin10000110100110…
…00000011101111
3100211120020201200
420122120003233
5242112211030
622000540543
73332413413
oct1032300357
9324506650
10141132015
1172735632
123b321753
132331568b
1414a5ad43
15c5cbd60
hex86980ef

141132015 has 12 divisors (see below), whose sum is σ = 244628904. Its totient is φ = 75270384.

The previous prime is 141132007. The next prime is 141132031. The reversal of 141132015 is 510231141.

It is not a de Polignac number, because 141132015 - 23 = 141132007 is a prime.

It is a super-3 number, since 3×1411320153 (a number of 25 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1568089 + ... + 1568178.

It is an arithmetic number, because the mean of its divisors is an integer number (20385742).

Almost surely, 2141132015 is an apocalyptic number.

141132015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

141132015 is a deficient number, since it is larger than the sum of its proper divisors (103496889).

141132015 is a wasteful number, since it uses less digits than its factorization.

141132015 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3136278 (or 3136275 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

The square root of 141132015 is about 11879.8996207880. The cubic root of 141132015 is about 520.6451742871.

Adding to 141132015 its reverse (510231141), we get a palindrome (651363156).

The spelling of 141132015 in words is "one hundred forty-one million, one hundred thirty-two thousand, fifteen".

Divisors: 1 3 5 9 15 45 3136267 9408801 15681335 28226403 47044005 141132015