1411331332240 has 20 divisors (see below), whose sum is σ = 3281345347644. Its totient is φ = 564532532864.

The previous prime is 1411331332223. The next prime is 1411331332249. The reversal of 1411331332240 is 422331331141.

It can be written as a sum of positive squares in 2 ways, for example, as 611580305296 + 799751026944 = 782036^2 + 894288^2 .

It is a tau number, because it is divible by the number of its divisors (20).

It is a super-2 number, since 2×1411331332240² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1411331332199 and 1411331332208.

It is not an unprimeable number, because it can be changed into a prime (1411331332249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8820820747 + ... + 8820820906.

Almost surely, 2^{1411331332240} is an apocalyptic number.

1411331332240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1411331332240 is an abundant number, since it is smaller than the sum of its proper divisors (1870014015404).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1411331332240 is a wasteful number, since it uses less digits than its factorization.

1411331332240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17641641666 (or 17641641660 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1411331332240 its reverse (422331331141), we get a palindrome (1833662663381).

The spelling of 1411331332240 in words is "one trillion, four hundred eleven billion, three hundred thirty-one million, three hundred thirty-two thousand, two hundred forty".