14113444431141 has 18 divisors (see below), whose sum is σ = 22407847037030. Its totient is φ = 8553602684880.

The previous prime is 14113444431127. The next prime is 14113444431157.

14113444431141 is a `hidden beast` number, since 1 + 4 + 11 + 34 + 44 + 431 + 141 = 666.

14113444431141 is nontrivially palindromic in base 10.

It can be written as a sum of positive squares in only one way, i.e., 13742746108641 + 370698322500 = 3707121^2 + 608850^2 .

It is not a de Polignac number, because 14113444431141 - 2⁶ = 14113444431077 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14113444431096 and 14113444431105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14113444432141) by changing a digit.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 6480000946 + ... + 6480003123.

Almost surely, 2^{14113444431141} is an apocalyptic number.

14113444431141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14113444431141 is a deficient number, since it is larger than the sum of its proper divisors (8294402605889).

14113444431141 is a wasteful number, since it uses less digits than its factorization.

14113444431141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12960004097 (or 12960004083 counting only the distinct ones).

The product of its digits is 36864, while the sum is 36.

It can be divided in two parts, 1411344 and 4431141, that added together give a palindrome (5842485).

The spelling of 14113444431141 in words is "fourteen trillion, one hundred thirteen billion, four hundred forty-four million, four hundred thirty-one thousand, one hundred forty-one".