Base | Representation |
---|---|
bin | 11010010010101000… |
… | …11101000001010111 |
3 | 1100102200212022110212 |
4 | 31021110131001113 |
5 | 212401420003112 |
6 | 10252341240035 |
7 | 1006532344454 |
oct | 151124350127 |
9 | 40380768425 |
10 | 14115000407 |
11 | 5a936057a2 |
12 | 289b10301b |
13 | 143c3a5261 |
14 | 97c89082b |
15 | 57929c522 |
hex | 34951d057 |
14115000407 has 2 divisors, whose sum is σ = 14115000408. Its totient is φ = 14115000406.
The previous prime is 14115000391. The next prime is 14115000409. The reversal of 14115000407 is 70400051141.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14115000407 - 24 = 14115000391 is a prime.
It is a super-2 number, since 2×141150004072 (a number of 21 digits) contains 22 as substring.
Together with 14115000409, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14115000409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057500203 + 7057500204.
It is an arithmetic number, because the mean of its divisors is an integer number (7057500204).
Almost surely, 214115000407 is an apocalyptic number.
14115000407 is a deficient number, since it is larger than the sum of its proper divisors (1).
14115000407 is an equidigital number, since it uses as much as digits as its factorization.
14115000407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 560, while the sum is 23.
Adding to 14115000407 its reverse (70400051141), we get a palindrome (84515051548).
The spelling of 14115000407 in words is "fourteen billion, one hundred fifteen million, four hundred seven", and thus it is an aban number.
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