Base | Representation |
---|---|
bin | 1000001110000000101… |
… | …1010001000000101000 |
3 | 111111110110201100112220 |
4 | 2003200023101000220 |
5 | 4303134200044422 |
6 | 144511050034040 |
7 | 13126032136440 |
oct | 2034013210050 |
9 | 444413640486 |
10 | 141200003112 |
11 | 549787a2253 |
12 | 23447718920 |
13 | 104133879cc |
14 | 6b96b5d120 |
15 | 3a1625ce5c |
hex | 20e02d1028 |
141200003112 has 128 divisors (see below), whose sum is σ = 429397770240. Its totient is φ = 37770808320.
The previous prime is 141200002991. The next prime is 141200003117. The reversal of 141200003112 is 211300002141.
It is a junction number, because it is equal to n+sod(n) for n = 141200003091 and 141200003100.
It is not an unprimeable number, because it can be changed into a prime (141200003117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 416073 + ... + 674919.
It is an arithmetic number, because the mean of its divisors is an integer number (3354670080).
Almost surely, 2141200003112 is an apocalyptic number.
141200003112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 141200003112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (214698885120).
141200003112 is an abundant number, since it is smaller than the sum of its proper divisors (288197767128).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141200003112 is a wasteful number, since it uses less digits than its factorization.
141200003112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 259071 (or 259067 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 141200003112 its reverse (211300002141), we get a palindrome (352500005253).
The spelling of 141200003112 in words is "one hundred forty-one billion, two hundred million, three thousand, one hundred twelve".
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