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141200003112 = 233717191258847
BaseRepresentation
bin1000001110000000101…
…1010001000000101000
3111111110110201100112220
42003200023101000220
54303134200044422
6144511050034040
713126032136440
oct2034013210050
9444413640486
10141200003112
11549787a2253
1223447718920
13104133879cc
146b96b5d120
153a1625ce5c
hex20e02d1028

141200003112 has 128 divisors (see below), whose sum is σ = 429397770240. Its totient is φ = 37770808320.

The previous prime is 141200002991. The next prime is 141200003117. The reversal of 141200003112 is 211300002141.

It is a junction number, because it is equal to n+sod(n) for n = 141200003091 and 141200003100.

It is not an unprimeable number, because it can be changed into a prime (141200003117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 416073 + ... + 674919.

It is an arithmetic number, because the mean of its divisors is an integer number (3354670080).

Almost surely, 2141200003112 is an apocalyptic number.

141200003112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 141200003112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (214698885120).

141200003112 is an abundant number, since it is smaller than the sum of its proper divisors (288197767128).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141200003112 is a wasteful number, since it uses less digits than its factorization.

141200003112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 259071 (or 259067 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 141200003112 its reverse (211300002141), we get a palindrome (352500005253).

The spelling of 141200003112 in words is "one hundred forty-one billion, two hundred million, three thousand, one hundred twelve".

Divisors: 1 2 3 4 6 7 8 12 14 17 21 24 28 34 42 51 56 68 84 102 119 136 168 191 204 238 357 382 408 476 573 714 764 952 1146 1337 1428 1528 2292 2674 2856 3247 4011 4584 5348 6494 8022 9741 10696 12988 16044 19482 22729 25976 32088 38964 45458 68187 77928 90916 136374 181832 258847 272748 517694 545496 776541 1035388 1553082 1811929 2070776 3106164 3623858 4400399 5435787 6212328 7247716 8800798 10871574 13201197 14495432 17601596 21743148 26402394 30802793 35203192 43486296 49439777 52804788 61605586 92408379 98879554 105609576 123211172 148319331 184816758 197759108 246422344 296638662 346078439 369633516 395518216 593277324 692156878 739267032 840476209 1038235317 1186554648 1384313756 1680952418 2076470634 2521428627 2768627512 3361904836 4152941268 5042857254 5883333463 6723809672 8305882536 10085714508 11766666926 17650000389 20171429016 23533333852 35300000778 47066667704 70600001556 141200003112