141201041433111 has 24 divisors (see below), whose sum is σ = 222767004854160. Its totient is φ = 85473160243200.

The previous prime is 141201041433079. The next prime is 141201041433143. The reversal of 141201041433111 is 111334140102141.

141201041433111 is a `hidden beast` number, since 1 + 4 + 1 + 201 + 0 + 4 + 143 + 311 + 1 = 666.

141201041433111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (141201041433079) and next prime (141201041433143).

It is not a de Polignac number, because 141201041433111 - 2⁵ = 141201041433079 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141201041433511) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 860155050 + ... + 860319191.

It is an arithmetic number, because the mean of its divisors is an integer number (9281958535590).

Almost surely, 2^{141201041433111} is an apocalyptic number.

141201041433111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

141201041433111 is a deficient number, since it is larger than the sum of its proper divisors (81565963421049).

141201041433111 is a wasteful number, since it uses less digits than its factorization.

141201041433111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1720475087 (or 1720475084 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 27.

Adding to 141201041433111 its reverse (111334140102141), we get a palindrome (252535181535252).

The spelling of 141201041433111 in words is "one hundred forty-one trillion, two hundred one billion, forty-one million, four hundred thirty-three thousand, one hundred eleven".