Base | Representation |
---|---|
bin | 1100110101111001110110… |
… | …1011110110011101110000 |
3 | 1211222212201020010001112120 |
4 | 3031132131223312131300 |
5 | 3322321133433121034 |
6 | 50010422014554240 |
7 | 2655102536226324 |
oct | 315363553663560 |
9 | 54885636101476 |
10 | 14120203020144 |
11 | 4554387545851 |
12 | 170070b508980 |
13 | 7b56b6212180 |
14 | 36b5c8741984 |
15 | 197473b07c49 |
hex | cd79daf6770 |
14120203020144 has 80 divisors (see below), whose sum is σ = 39292890844032. Its totient is φ = 4343598192384.
The previous prime is 14120203020137. The next prime is 14120203020173. The reversal of 14120203020144 is 44102030202141.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 296754 + ... + 5322449.
Almost surely, 214120203020144 is an apocalyptic number.
It is an amenable number.
14120203020144 is an abundant number, since it is smaller than the sum of its proper divisors (25172687823888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14120203020144 is a wasteful number, since it uses less digits than its factorization.
14120203020144 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5623254 (or 5623248 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 14120203020144 its reverse (44102030202141), we get a palindrome (58222233222285).
The spelling of 14120203020144 in words is "fourteen trillion, one hundred twenty billion, two hundred three million, twenty thousand, one hundred forty-four".
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