Base | Representation |
---|---|
bin | 1100110101111010000010… |
… | …0111111011110010010101 |
3 | 1211222212211122220000002211 |
4 | 3031132200213323302111 |
5 | 3322321234043400023 |
6 | 50010430535433421 |
7 | 2655104005300312 |
oct | 315364047736225 |
9 | 54885748800084 |
10 | 14120252325013 |
11 | 455440236127a |
12 | 1700723b25871 |
13 | 7b56c34b6053 |
14 | 36b5d10d7d09 |
15 | 1974780e6a0d |
hex | cd7a09fbc95 |
14120252325013 has 4 divisors (see below), whose sum is σ = 14734176339168. Its totient is φ = 13506328310860.
The previous prime is 14120252325007. The next prime is 14120252325041. The reversal of 14120252325013 is 31052325202141.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14120252325013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14120252325083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 306962007043 + ... + 306962007088.
It is an arithmetic number, because the mean of its divisors is an integer number (3683544084792).
Almost surely, 214120252325013 is an apocalyptic number.
It is an amenable number.
14120252325013 is a deficient number, since it is larger than the sum of its proper divisors (613924014155).
14120252325013 is an equidigital number, since it uses as much as digits as its factorization.
14120252325013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 613924014154.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 14120252325013 its reverse (31052325202141), we get a palindrome (45172577527154).
The spelling of 14120252325013 in words is "fourteen trillion, one hundred twenty billion, two hundred fifty-two million, three hundred twenty-five thousand, thirteen".
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