Base | Representation |
---|---|
bin | 100000000110110001100010… |
… | …101110001111011101100100 |
3 | 200111221212121221001221212111 |
4 | 200012301202232033131210 |
5 | 122001432221241044140 |
6 | 1220151432503530404 |
7 | 41512403000030032 |
oct | 4006614256173544 |
9 | 614855557057774 |
10 | 141203001112420 |
11 | 40a9a946a78535 |
12 | 13a06107459a04 |
13 | 60a35029ac070 |
14 | 26c239422b552 |
15 | 114d0328da7ea |
hex | 806c62b8f764 |
141203001112420 has 96 divisors (see below), whose sum is σ = 320623817947776. Its totient is φ = 51926259840000.
The previous prime is 141203001112409. The next prime is 141203001112421. The reversal of 141203001112420 is 24211100302141.
It is a junction number, because it is equal to n+sod(n) for n = 141203001112391 and 141203001112400.
It is not an unprimeable number, because it can be changed into a prime (141203001112421) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1841011512 + ... + 1841088208.
It is an arithmetic number, because the mean of its divisors is an integer number (3339831436956).
Almost surely, 2141203001112420 is an apocalyptic number.
141203001112420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 141203001112420, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (160311908973888).
141203001112420 is an abundant number, since it is smaller than the sum of its proper divisors (179420816835356).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141203001112420 is a wasteful number, since it uses less digits than its factorization.
141203001112420 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 105181 (or 105179 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 141203001112420 its reverse (24211100302141), we get a palindrome (165414101414561).
The spelling of 141203001112420 in words is "one hundred forty-one trillion, two hundred three billion, one million, one hundred twelve thousand, four hundred twenty".
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