141333101234240 has 112 divisors (see below), whose sum is σ = 338340896575680. Its totient is φ = 56232784742400.

The previous prime is 141333101234209. The next prime is 141333101234257. The reversal of 141333101234240 is 42432101333141.

It is a super-3 number, since 3×141333101234240³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (32).

It is a junction number, because it is equal to n+sod(n) for n = 141333101234197 and 141333101234206.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 76099739 + ... + 77934821.

Almost surely, 2^{141333101234240} is an apocalyptic number.

141333101234240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 141333101234240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (169170448287840).

141333101234240 is an abundant number, since it is smaller than the sum of its proper divisors (197007795341440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141333101234240 is a wasteful number, since it uses less digits than its factorization.

141333101234240 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1836380 (or 1836370 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 141333101234240 its reverse (42432101333141), we get a palindrome (183765202567381).

The spelling of 141333101234240 in words is "one hundred forty-one trillion, three hundred thirty-three billion, one hundred one million, two hundred thirty-four thousand, two hundred forty".