1414113120 has 384 divisors, whose sum is σ = 5724794880. Its totient is φ = 319334400.

The previous prime is 1414113119. The next prime is 1414113161. The reversal of 1414113120 is 213114141.

It is a super-2 number, since 2×1414113120² = 3999431832312268800, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1414113093 and 1414113102.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3054009 + ... + 3054471.

It is an arithmetic number, because the mean of its divisors is an integer number (14908320).

Almost surely, 2^1414113120 is an apocalyptic number.

1414113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1414113120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2862397440).

1414113120 is an abundant number, since it is smaller than the sum of its proper divisors (4310681760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1414113120 is a wasteful number, since it uses less digits than its factorization.

1414113120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 595 (or 581 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

The square root of 1414113120 is about 37604.6954514991. The cubic root of 1414113120 is about 1122.4354739588.

Adding to 1414113120 its reverse (213114141), we get a palindrome (1627227261).

It can be divided in two parts, 14141 and 13120, that added together give a triangular number (27261 = T₂₃₃).

The spelling of 1414113120 in words is "one billion, four hundred fourteen million, one hundred thirteen thousand, one hundred twenty".