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14210211335 = 55321011763
BaseRepresentation
bin11010011101111111…
…01001111000000111
31100200100000112022112
431032333221320013
5213100303230320
610310022051235
71012066542365
oct151677517007
940610015275
1014210211335
116032326111
122906b79b1b
13145602cc98
1498b396635
15582807ec5
hex34efe9e07

14210211335 has 12 divisors (see below), whose sum is σ = 17380081992. Its totient is φ = 11153664288.

The previous prime is 14210211259. The next prime is 14210211343. The reversal of 14210211335 is 53311201241.

It is not a de Polignac number, because 14210211335 - 28 = 14210211079 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14210211335.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 491837 + ... + 519926.

It is an arithmetic number, because the mean of its divisors is an integer number (1448340166).

Almost surely, 214210211335 is an apocalyptic number.

14210211335 is a deficient number, since it is larger than the sum of its proper divisors (3169870657).

14210211335 is an equidigital number, since it uses as much as digits as its factorization.

14210211335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1011874 (or 1011821 counting only the distinct ones).

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 14210211335 its reverse (53311201241), we get a palindrome (67521412576).

The spelling of 14210211335 in words is "fourteen billion, two hundred ten million, two hundred eleven thousand, three hundred thirty-five".

Divisors: 1 5 53 265 2809 14045 1011763 5058815 53623439 268117195 2842042267 14210211335