Base | Representation |
---|---|
bin | 10100101011100000111… |
… | …111101111101001111111 |
3 | 12000212010212201212002210 |
4 | 110223200333233221333 |
5 | 141240420141424320 |
6 | 3004503433151503 |
7 | 204446346546111 |
oct | 24534077575177 |
9 | 5025125655083 |
10 | 1421114014335 |
11 | 4a87668a3814 |
12 | 1ab50825b593 |
13 | a401a02b292 |
14 | 4cad483b3b1 |
15 | 26e76ace0e0 |
hex | 14ae0fefa7f |
1421114014335 has 8 divisors (see below), whose sum is σ = 2273782422960. Its totient is φ = 757927474304.
The previous prime is 1421114014319. The next prime is 1421114014349. The reversal of 1421114014335 is 5334104111241.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1421114014335 - 24 = 1421114014319 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47370467130 + ... + 47370467159.
It is an arithmetic number, because the mean of its divisors is an integer number (284222802870).
Almost surely, 21421114014335 is an apocalyptic number.
1421114014335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1421114014335 is a deficient number, since it is larger than the sum of its proper divisors (852668408625).
1421114014335 is an equidigital number, since it uses as much as digits as its factorization.
1421114014335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 94740934297.
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 1421114014335 its reverse (5334104111241), we get a palindrome (6755218125576).
The spelling of 1421114014335 in words is "one trillion, four hundred twenty-one billion, one hundred fourteen million, fourteen thousand, three hundred thirty-five".
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