1421131054350 has 48 divisors (see below), whose sum is σ = 4027891448448. Its totient is φ = 324829955040.

The previous prime is 1421131054333. The next prime is 1421131054351. The reversal of 1421131054350 is 534501311241.

It is a super-2 number, since 2×1421131054350² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1421131054351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 676728024 + ... + 676730123.

It is an arithmetic number, because the mean of its divisors is an integer number (83914405176).

Almost surely, 2^{1421131054350} is an apocalyptic number.

1421131054350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1421131054350 is an abundant number, since it is smaller than the sum of its proper divisors (2606760394098).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1421131054350 is a wasteful number, since it uses less digits than its factorization.

1421131054350 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1353458169 (or 1353458164 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 30.

Adding to 1421131054350 its reverse (534501311241), we get a palindrome (1955632365591).

The spelling of 1421131054350 in words is "one trillion, four hundred twenty-one billion, one hundred thirty-one million, fifty-four thousand, three hundred fifty".