Base | Representation |
---|---|
bin | 1100111011010011100011… |
… | …0100001111110110111000 |
3 | 1212022202020102000012211112 |
4 | 3032310320310033312320 |
5 | 3330331211000044000 |
6 | 50121210112215452 |
7 | 2664566250454001 |
oct | 316647064176670 |
9 | 55282212005745 |
10 | 14213000003000 |
11 | 458a776a73517 |
12 | 17166a8b3a588 |
13 | 7c1384646296 |
14 | 371caccba1a8 |
15 | 199aa57c5235 |
hex | ced38d0fdb8 |
14213000003000 has 64 divisors (see below), whose sum is σ = 33265665576000. Its totient is φ = 5683961443200.
The previous prime is 14213000002979. The next prime is 14213000003023. The reversal of 14213000003000 is 30000031241.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3051101 + ... + 6142899.
It is an arithmetic number, because the mean of its divisors is an integer number (519776024625).
Almost surely, 214213000003000 is an apocalyptic number.
14213000003000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14213000003000 is an abundant number, since it is smaller than the sum of its proper divisors (19052665573000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14213000003000 is a wasteful number, since it uses less digits than its factorization.
14213000003000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3096417 (or 3096403 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 14.
Adding to 14213000003000 its reverse (30000031241), we get a palindrome (14243000034241).
The spelling of 14213000003000 in words is "fourteen trillion, two hundred thirteen billion, three thousand".
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