Base | Representation |
---|---|
bin | 1000010001011110110… |
… | …0000010001011100111 |
3 | 111120212101012011120222 |
4 | 2010113230002023213 |
5 | 4312041110340012 |
6 | 145143315514555 |
7 | 13161101312366 |
oct | 2042754021347 |
9 | 446771164528 |
10 | 142131340007 |
11 | 55306488468 |
12 | 236675b8a5b |
13 | 10531303a27 |
14 | 6c447157dd |
15 | 3a6cdc9972 |
hex | 2117b022e7 |
142131340007 has 2 divisors, whose sum is σ = 142131340008. Its totient is φ = 142131340006.
The previous prime is 142131339929. The next prime is 142131340031. The reversal of 142131340007 is 700043131241.
It is a strong prime.
It is an emirp because it is prime and its reverse (700043131241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 142131340007 - 214 = 142131323623 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142131340907) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71065670003 + 71065670004.
It is an arithmetic number, because the mean of its divisors is an integer number (71065670004).
Almost surely, 2142131340007 is an apocalyptic number.
142131340007 is a deficient number, since it is larger than the sum of its proper divisors (1).
142131340007 is an equidigital number, since it uses as much as digits as its factorization.
142131340007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 26.
Adding to 142131340007 its reverse (700043131241), we get a palindrome (842174471248).
The spelling of 142131340007 in words is "one hundred forty-two billion, one hundred thirty-one million, three hundred forty thousand, seven".
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