1421343521335 has 4 divisors (see below), whose sum is σ = 1705612225608. Its totient is φ = 1137074817064.

The previous prime is 1421343521329. The next prime is 1421343521359. The reversal of 1421343521335 is 5331253431241.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1421343521335 - 2⁵ = 1421343521303 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1421343521294 and 1421343521303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142134352129 + ... + 142134352138.

It is an arithmetic number, because the mean of its divisors is an integer number (426403056402).

Almost surely, 2^{1421343521335} is an apocalyptic number.

1421343521335 is a deficient number, since it is larger than the sum of its proper divisors (284268704273).

1421343521335 is an equidigital number, since it uses as much as digits as its factorization.

1421343521335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 284268704272.

The product of its digits is 129600, while the sum is 37.

Adding to 1421343521335 its reverse (5331253431241), we get a palindrome (6752596952576).

The spelling of 1421343521335 in words is "one trillion, four hundred twenty-one billion, three hundred forty-three million, five hundred twenty-one thousand, three hundred thirty-five".