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14226547997 is a prime number
BaseRepresentation
bin11010011111111011…
…11110010100011101
31100201110202112000002
431033331332110131
5213113444013442
610311404144045
71012355443214
oct151775762435
940643675002
1014226547997
116040574092
122910538025
13145952cb4c
1498d60a07b
15583e83732
hex34ff7e51d

14226547997 has 2 divisors, whose sum is σ = 14226547998. Its totient is φ = 14226547996.

The previous prime is 14226547991. The next prime is 14226547999. The reversal of 14226547997 is 79974562241.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14173854916 + 52693081 = 119054^2 + 7259^2 .

It is a cyclic number.

It is not a de Polignac number, because 14226547997 - 24 = 14226547981 is a prime.

Together with 14226547999, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14226547991) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7113273998 + 7113273999.

It is an arithmetic number, because the mean of its divisors is an integer number (7113273999).

Almost surely, 214226547997 is an apocalyptic number.

It is an amenable number.

14226547997 is a deficient number, since it is larger than the sum of its proper divisors (1).

14226547997 is an equidigital number, since it uses as much as digits as its factorization.

14226547997 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7620480, while the sum is 56.

The spelling of 14226547997 in words is "fourteen billion, two hundred twenty-six million, five hundred forty-seven thousand, nine hundred ninety-seven".