142300031400335 has 8 divisors (see below), whose sum is σ = 170760286761696. Its totient is φ = 113839859066080.

The previous prime is 142300031400313. The next prime is 142300031400337. The reversal of 142300031400335 is 533004130003241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2^k-142300031400335 is a prime.

It is a super-2 number, since 2×142300031400335² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142300031400298 and 142300031400307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142300031400337) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16921784 + ... + 23894493.

It is an arithmetic number, because the mean of its divisors is an integer number (21345035845212).

Almost surely, 2^{142300031400335} is an apocalyptic number.

142300031400335 is a deficient number, since it is larger than the sum of its proper divisors (28460255361361).

142300031400335 is an equidigital number, since it uses as much as digits as its factorization.

142300031400335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41513553.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 142300031400335 its reverse (533004130003241), we get a palindrome (675304161403576).

The spelling of 142300031400335 in words is "one hundred forty-two trillion, three hundred billion, thirty-one million, four hundred thousand, three hundred thirty-five".