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14234121335 = 571721407229
BaseRepresentation
bin11010100000110101…
…10111010001110111
31100202000000021200002
431100122313101313
5213122413340320
610312234341515
71012510015010
oct152032672167
940660007602
1014234121335
116044877045
122912b8a89b
13145ac82005
1499061c007
1558497c675
hex3506b7477

14234121335 has 24 divisors (see below), whose sum is σ = 20736941280. Its totient is φ = 9186384384.

The previous prime is 14234121289. The next prime is 14234121361. The reversal of 14234121335 is 53312143241.

It is not a de Polignac number, because 14234121335 - 218 = 14233859191 is a prime.

It is a super-2 number, since 2×142341213352 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14234121298 and 14234121307.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 693500 + ... + 713729.

It is an arithmetic number, because the mean of its divisors is an integer number (864039220).

Almost surely, 214234121335 is an apocalyptic number.

14234121335 is a deficient number, since it is larger than the sum of its proper divisors (6502819945).

14234121335 is a wasteful number, since it uses less digits than its factorization.

14234121335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1407275 (or 1407258 counting only the distinct ones).

The product of its digits is 8640, while the sum is 29.

Adding to 14234121335 its reverse (53312143241), we get a palindrome (67546264576).

The spelling of 14234121335 in words is "fourteen billion, two hundred thirty-four million, one hundred twenty-one thousand, three hundred thirty-five".

Divisors: 1 5 7 17 35 85 119 289 595 1445 2023 10115 1407229 7036145 9850603 23922893 49253015 119614465 167460251 406689181 837301255 2033445905 2846824267 14234121335