Base | Representation |
---|---|
bin | 11010100000110101… |
… | …10111010001110111 |
3 | 1100202000000021200002 |
4 | 31100122313101313 |
5 | 213122413340320 |
6 | 10312234341515 |
7 | 1012510015010 |
oct | 152032672167 |
9 | 40660007602 |
10 | 14234121335 |
11 | 6044877045 |
12 | 2912b8a89b |
13 | 145ac82005 |
14 | 99061c007 |
15 | 58497c675 |
hex | 3506b7477 |
14234121335 has 24 divisors (see below), whose sum is σ = 20736941280. Its totient is φ = 9186384384.
The previous prime is 14234121289. The next prime is 14234121361. The reversal of 14234121335 is 53312143241.
It is not a de Polignac number, because 14234121335 - 218 = 14233859191 is a prime.
It is a super-2 number, since 2×142341213352 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14234121298 and 14234121307.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 693500 + ... + 713729.
It is an arithmetic number, because the mean of its divisors is an integer number (864039220).
Almost surely, 214234121335 is an apocalyptic number.
14234121335 is a deficient number, since it is larger than the sum of its proper divisors (6502819945).
14234121335 is a wasteful number, since it uses less digits than its factorization.
14234121335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1407275 (or 1407258 counting only the distinct ones).
The product of its digits is 8640, while the sum is 29.
Adding to 14234121335 its reverse (53312143241), we get a palindrome (67546264576).
The spelling of 14234121335 in words is "fourteen billion, two hundred thirty-four million, one hundred twenty-one thousand, three hundred thirty-five".
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