Base | Representation |
---|---|
bin | 100000010111100010011101… |
… | …100101111000101011100110 |
3 | 200200001000020111111210001111 |
4 | 200113202131211320223212 |
5 | 122124321110220404110 |
6 | 1222433000315415234 |
7 | 41661545412101005 |
oct | 4027423545705346 |
9 | 620030214453044 |
10 | 142355040013030 |
11 | 413a44849987a9 |
12 | 13b7143aa5451a |
13 | 615803aa71700 |
14 | 2722040b28c3c |
15 | 116ceabc29e8a |
hex | 81789d978ae6 |
142355040013030 has 24 divisors (see below), whose sum is σ = 277465977401472. Its totient is φ = 52561860927264.
The previous prime is 142355040012949. The next prime is 142355040013033. The reversal of 142355040013030 is 30310040553241.
142355040013030 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×1423550400130303 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 142355040012983 and 142355040013001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142355040013033) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 42116874054 + ... + 42116877433.
It is an arithmetic number, because the mean of its divisors is an integer number (11561082391728).
Almost surely, 2142355040013030 is an apocalyptic number.
142355040013030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
142355040013030 is a deficient number, since it is larger than the sum of its proper divisors (135110937388442).
142355040013030 is a wasteful number, since it uses less digits than its factorization.
142355040013030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84233751520 (or 84233751507 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 142355040013030 its reverse (30310040553241), we get a palindrome (172665080566271).
The spelling of 142355040013030 in words is "one hundred forty-two trillion, three hundred fifty-five billion, forty million, thirteen thousand, thirty".
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