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142400450111 is a prime number
BaseRepresentation
bin1000010010011110111…
…0100110111000111111
3111121120010120101020212
42010213232212320333
54313114003400421
6145230131503035
713200546566063
oct2044756467077
9447503511225
10142400450111
1155434383907
1223721757a7b
1310574ca778a
146c6c367aa3
153a86835e5b
hex2127ba6e3f

142400450111 has 2 divisors, whose sum is σ = 142400450112. Its totient is φ = 142400450110.

The previous prime is 142400450099. The next prime is 142400450113. The reversal of 142400450111 is 111054004241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 142400450111 - 26 = 142400450047 is a prime.

Together with 142400450113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142400450113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71200225055 + 71200225056.

It is an arithmetic number, because the mean of its divisors is an integer number (71200225056).

Almost surely, 2142400450111 is an apocalyptic number.

142400450111 is a deficient number, since it is larger than the sum of its proper divisors (1).

142400450111 is an equidigital number, since it uses as much as digits as its factorization.

142400450111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 640, while the sum is 23.

Adding to 142400450111 its reverse (111054004241), we get a palindrome (253454454352).

The spelling of 142400450111 in words is "one hundred forty-two billion, four hundred million, four hundred fifty thousand, one hundred eleven".