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142514000501340 = 223513417013635441
BaseRepresentation
bin100000011001110110100000…
…011000000001101001011100
3200200121012112201201021002110
4200121312200120001221130
5122134422133112020330
61223034010014354020
742006203534000616
oct4031664030015134
9620535481637073
10142514000501340
1141455936a50396
1213b982024bb910
13616a021848950
142729a00567db6
1511721b22cddb0
hex819da0601a5c

142514000501340 has 192 divisors, whose sum is σ = 440279318731392. Its totient is φ = 34219816550400.

The previous prime is 142514000501333. The next prime is 142514000501347. The reversal of 142514000501340 is 43105000415241.

It is an interprime number because it is at equal distance from previous prime (142514000501333) and next prime (142514000501347).

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 142514000501298 and 142514000501307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142514000501347) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 223958020 + ... + 224593460.

It is an arithmetic number, because the mean of its divisors is an integer number (2293121451726).

Almost surely, 2142514000501340 is an apocalyptic number.

142514000501340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 142514000501340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (220139659365696).

142514000501340 is an abundant number, since it is smaller than the sum of its proper divisors (297765318230052).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

142514000501340 is a wasteful number, since it uses less digits than its factorization.

142514000501340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 642520 (or 642518 counting only the distinct ones).

The product of its (nonzero) digits is 9600, while the sum is 30.

Adding to 142514000501340 its reverse (43105000415241), we get a palindrome (185619000916581).

The spelling of 142514000501340 in words is "one hundred forty-two trillion, five hundred fourteen billion, five hundred one thousand, three hundred forty".