Base | Representation |
---|---|
bin | 1101000000011011110000… |
… | …1010111110101010110000 |
3 | 1212122011122110120102221111 |
4 | 3100012330022332222300 |
5 | 3333302124344414440 |
6 | 50225500332003104 |
7 | 3004135444564342 |
oct | 320067412765260 |
9 | 55564573512844 |
10 | 14301103123120 |
11 | 461407797a690 |
12 | 172b796600494 |
13 | 7c9785487c18 |
14 | 376269cc3292 |
15 | 19c01035d4ea |
hex | d01bc2beab0 |
14301103123120 has 80 divisors (see below), whose sum is σ = 36444707389440. Its totient is φ = 5175754617600.
The previous prime is 14301103123103. The next prime is 14301103123129. The reversal of 14301103123120 is 2132130110341.
It is a tau number, because it is divible by the number of its divisors (80).
It is a super-2 number, since 2×143011031231202 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a junction number, because it is equal to n+sod(n) for n = 14301103123091 and 14301103123100.
It is not an unprimeable number, because it can be changed into a prime (14301103123129) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38324400 + ... + 38695759.
It is an arithmetic number, because the mean of its divisors is an integer number (455558842368).
Almost surely, 214301103123120 is an apocalyptic number.
14301103123120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14301103123120 is an abundant number, since it is smaller than the sum of its proper divisors (22143604266320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14301103123120 is a wasteful number, since it uses less digits than its factorization.
14301103123120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 77020394 (or 77020388 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 14301103123120 its reverse (2132130110341), we get a palindrome (16433233233461).
The spelling of 14301103123120 in words is "fourteen trillion, three hundred one billion, one hundred three million, one hundred twenty-three thousand, one hundred twenty".
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