Base | Representation |
---|---|
bin | 101010100111111… |
… | …0101010111110100 |
3 | 10200200012101221210 |
4 | 1111033311113310 |
5 | 10412113323012 |
6 | 353530241420 |
7 | 50304422334 |
oct | 12517652764 |
9 | 3620171853 |
10 | 1430214132 |
11 | 674356056 |
12 | 33ab86270 |
13 | 19a3ca069 |
14 | d7d390c4 |
15 | 8586223c |
hex | 553f55f4 |
1430214132 has 72 divisors (see below), whose sum is σ = 3617646816. Its totient is φ = 439390656.
The previous prime is 1430214101. The next prime is 1430214133. The reversal of 1430214132 is 2314120341.
It is a junction number, because it is equal to n+sod(n) for n = 1430214099 and 1430214108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1430214133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 155823 + ... + 164745.
Almost surely, 21430214132 is an apocalyptic number.
1430214132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1430214132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1808823408).
1430214132 is an abundant number, since it is smaller than the sum of its proper divisors (2187432684).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1430214132 is a wasteful number, since it uses less digits than its factorization.
1430214132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9005 (or 8984 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 21.
The square root of 1430214132 is about 37818.1719812050. The cubic root of 1430214132 is about 1126.6794030437.
Adding to 1430214132 its reverse (2314120341), we get a palindrome (3744334473).
It can be divided in two parts, 143021 and 4132, that added together give a triangular number (147153 = T542).
The spelling of 1430214132 in words is "one billion, four hundred thirty million, two hundred fourteen thousand, one hundred thirty-two".
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