Base | Representation |
---|---|
bin | 11010101001111010… |
… | …01000101100000000 |
3 | 1100221022012012201202 |
4 | 31110331020230000 |
5 | 213301403330100 |
6 | 10323553320332 |
7 | 1014422546456 |
oct | 152475105400 |
9 | 40838165652 |
10 | 14310214400 |
11 | 6083819979 |
12 | 29345660a8 |
13 | 1470974cb1 |
14 | 99a7889d6 |
15 | 58b4ad7d5 |
hex | 354f48b00 |
14310214400 has 54 divisors (see below), whose sum is σ = 35420032452. Its totient is φ = 5724083200.
The previous prime is 14310214367. The next prime is 14310214411. The reversal of 14310214400 is 441201341.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1111586 + ... + 1124385.
Almost surely, 214310214400 is an apocalyptic number.
14310214400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14310214400 is an abundant number, since it is smaller than the sum of its proper divisors (21109818052).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14310214400 is an equidigital number, since it uses as much as digits as its factorization.
14310214400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2235997 (or 2235978 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 14310214400 its reverse (441201341), we get a palindrome (14751415741).
The spelling of 14310214400 in words is "fourteen billion, three hundred ten million, two hundred fourteen thousand, four hundred".
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