143111132040 has 32 divisors (see below), whose sum is σ = 429333396480. Its totient is φ = 38162968512.

The previous prime is 143111131987. The next prime is 143111132053. The reversal of 143111132040 is 40231111341.

It is a super-2 number, since 2×143111132040² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143111131998 and 143111132016.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 596296264 + ... + 596296503.

It is an arithmetic number, because the mean of its divisors is an integer number (13416668640).

Almost surely, 2^143111132040 is an apocalyptic number.

143111132040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

143111132040 is an abundant number, since it is smaller than the sum of its proper divisors (286222264440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143111132040 is a wasteful number, since it uses less digits than its factorization.

143111132040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1192592781 (or 1192592777 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 143111132040 its reverse (40231111341), we get a palindrome (183342243381).

The spelling of 143111132040 in words is "one hundred forty-three billion, one hundred eleven million, one hundred thirty-two thousand, forty".